Joomla 2.5 - Fehler 500

Hast Du vielleicht noch ein Backup deiner Datenbank? Dann kannst Du dir den passenden Teil raussuchen und ihn in myphpadmin wieder einfügen.
Du kannst auch versuchen im Joomla Backend auf Erweiterungen=>Datenbank gehen und schauen, schauen ob er dir da was zum reparieren anbietet.
Du kannst auch in ein aktuelles Joomla Installationspaket schauen im Ordner
administrator/components/com_contact/sql/ findest Du die Datei install.mysql.utf8.sql
die kannst Du an dein Tabellen-Suffix ( in deinem Fall j25_ )anpassen und damit wieder die Datenbank-Einträge erzeugen.

Guten Abend nochmal

Bekomme seit heute folgenden fehler wenn ich mir ein Beitrag ansehen möchte:


500
Fehler: 500

Table 'db347429969.j25_contact_details' doesn't exist SQL=SELECT a.id, a.title, a.alias, a.title_alias, a.introtext, a.checked_out, a.checked_out_time, a.catid, a.created, a.created_by, a.created_by_alias, CASE WHEN a.modified = 0 THEN a.created ELSE a.modified END as modified, a.modified_by, uam.name as modified_by_name,CASE WHEN a.publish_up = 0 THEN a.created ELSE a.publish_up END as publish_up,a.publish_down, a.images, a.urls, a.attribs, a.metadata, a.metakey, a.metadesc, a.access, a.hits, a.xreference, a.featured, LENGTH(a.fulltext) AS readmore,CASE WHEN badcats.id is not null THEN 0 ELSE a.state END AS state,c.title AS category_title, c.path AS category_route, c.access AS category_access, c.alias AS category_alias,CASE WHEN a.created_by_alias > ' ' THEN a.created_by_alias ELSE ua.name END AS author,ua.email AS author_email,contact.id as contactid,parent.title as parent_title, parent.id as parent_id, parent.path as parent_route, parent.alias as parent_alias,ROUND(v.rating_sum / v.rating_count, 0) AS rating, v.rating_count as rating_count,c.published, CASE WHEN badcats.id is null THEN c.published ELSE 0 END AS parents_published FROM j25_content AS a LEFT JOIN j25_content_frontpage AS fp ON fp.content_id = a.id LEFT JOIN j25_categories AS c ON c.id = a.catid LEFT JOIN j25_users AS ua ON ua.id = a.created_by LEFT JOIN j25_users AS uam ON uam.id = a.modified_by LEFT JOIN ( SELECT contact.user_id, MAX(contact.id) AS id, contact.language FROM j25_contact_details AS contact WHERE contact.published = 1 GROUP BY contact.user_id, contact.language) AS contact ON contact.user_id = a.created_by LEFT JOIN j25_categories as parent ON parent.id = c.parent_id LEFT JOIN j25_content_rating AS v ON a.id = v.content_id LEFT OUTER JOIN (SELECT cat.id as id FROM j25_categories AS cat JOIN j25_categories AS parent ON cat.lft BETWEEN parent.lft AND parent.rgt WHERE parent.extension = 'com_content' AND parent.published != 1 GROUP BY cat.id ) AS badcats ON badcats.id = c.id WHERE a.access IN (1,1,2,3,4) AND CASE WHEN badcats.id is null THEN a.state ELSE 0 END IN (0,1,2) AND a.catid = 2 AND (a.publish_up = '0000-00-00 00:00:00' OR a.publish_up <= '2012-10-24 21:41:54') AND (a.publish_down = '0000-00-00 00:00:00' OR a.publish_down >= '2012-10-24 21:41:54') GROUP BY a.id, a.title, a.alias, a.title_alias, a.introtext, a.checked_out, a.checked_out_time, a.catid, a.created, a.created_by, a.created_by_alias, a.created, a.modified, a.modified_by, uam.name, a.publish_up, a.attribs, a.metadata, a.metakey, a.metadesc, a.access, a.hits, a.xreference, a.featured, a.fulltext, a.state, a.publish_down, badcats.id, c.title, c.path, c.access, c.alias, uam.id, ua.name, ua.email, contact.id, parent.title, parent.id, parent.path, parent.alias, v.rating_sum, v.rating_count, c.published, c.lft, a.ordering, parent.lft, fp.ordering, c.id, a.images, a.urls ORDER BY a.created DESC , a.created LIMIT 0, 9


Ich habe heute (glaube ich) die "Joomla Intigrierte Kontate Komponente" gelöscht... Kann das daran liegen? Habe in meiner DB schon nachgeschaut dort ist die Tabelle wirklich nicht da...

Hat jemand eine Idee oder eine Lösung? :blush:

Eine Gute nacht noch!